f ( 1 3 ) = 3 − 1 3 − 1 −−−−−√ = 3 − 1 2 −−√

a four-sided triangle

three times four

0 3 5 5 0 1 3 1 3 1

x = √ 4 5 y + 1 2 5 z

x = √ 4 5 y + 1 2 5 z, by rutkowski

the year 1 9 3 3

3 🤯 1 2 🐌 🤹♂

the three - body problem

the square root of negative one

iris van herpen = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = kitchenaid stand mixer

1 2 9 8 4 3 2 3 3 4

iris van herpen = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = kitchenaid stand mixer

x \ = \ √ 4 5 y \ + 1 2 5 z, by rutkowski

3 d illustration conical shape, with triangle

the year 2 0 1 3

vector geometric shape, pentagon

1 0 hexagons, 1 triangle, and 1 square

🛰 🌈 🕳 geometric abstract triangle

answer to 1 + 1 maths problem

infinite series triangle becomes circle mc escher

sketch of a triangle that looks 3d but isn't

3. 1 4 1 5 9 2 6

f ( x ) = 3 x 2 + 3 x − 4

realistic 3 6 2 4 6 7 3 4 7 6 6 1 2 6 3 2 3 4